What are the solutions to the equation 64r^2+1=26 ?

The solutions to the equation 64r^2+1=26 are r= 5/8 ,r=-5/8

Find the zeros of 64r^2+1=26

The zeros of 64r^2+1=26 are r= 5/8 ,r=-5/8

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64 r^{2} + 1 = 26

r = \frac{5}{8}, r = - \frac{5}{8}

Decimal Notation

r = 0.625, r = - 0.625

Solution steps

64 r^{2} + 1 = 26

Move

1

to the right side

64 r^{2} = 25

Divide both sides by

64

r^{2} = \frac{25}{64}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{25}{64}, r = - \frac{25}{64}

\frac{25}{64} = \frac{5}{8}

- \frac{25}{64} = - \frac{5}{8}

r = \frac{5}{8}, r = - \frac{5}{8}

(3 x - 2)^{2} = 7

5 x^{2} + 6 = 6

(4 x + 7)^{2} = (7 x + 4)^{2}

2 x^{2} - 16 x + 24 = 0

X^{1} + X^{2} = 103

What are the solutions to the equation 64r^2+1=26 ?
The solutions to the equation 64r^2+1=26 are r= 5/8 ,r=-5/8
Find the zeros of 64r^2+1=26
The zeros of 64r^2+1=26 are r= 5/8 ,r=-5/8