What are the solutions to the equation x^2+8x+16=144 ?

The solutions to the equation x^2+8x+16=144 are x=8,x=-16

Find the zeros of x^2+8x+16=144

The zeros of x^2+8x+16=144 are x=8,x=-16

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x^{2} + 8 x + 16 = 144

x = 8, x = - 16

Solution steps

x^{2} + 8 x + 16 = 144

Move

144

to the left side

x^{2} + 8 x - 128 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 128 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 128) = 24

x_{1, 2} = \frac{- 8 \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 24}{2 \cdot 1}, x_{2} = \frac{- 8 - 24}{2 \cdot 1}

x = \frac{- 8 + 24}{2 \cdot 1} : 8

x = \frac{- 8 - 24}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 8, x = - 16

t, r (t) = 300 t - 300 t^{2}

1 7^{2} = x^{2} + (x + 7)^{2}

t, t^{2} + 12 t + a = 0

x^{2} - 11 x + 25 = 0

4 h^{2} = 3 l^{2}

What are the solutions to the equation x^2+8x+16=144 ?
The solutions to the equation x^2+8x+16=144 are x=8,x=-16
Find the zeros of x^2+8x+16=144
The zeros of x^2+8x+16=144 are x=8,x=-16