What are the solutions to the equation 4w^2-20w=0 ?

The solutions to the equation 4w^2-20w=0 are w=5,w=0

Find the zeros of 4w^2-20w=0

The zeros of 4w^2-20w=0 are w=5,w=0

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4 w^{2} - 20 w = 0

w = 5, w = 0

Solution steps

4 w^{2} - 20 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 0 = 20

w_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 4}, w_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 4}

w = \frac{- ( - 20 ) + 20}{2 \cdot 4} : 5

w = \frac{- ( - 20 ) - 20}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

w = 5, w = 0

x^{2} + 22 x = - 85

(x - 12)^{2} = 625

x, 2 cos (x) - sin (x \cdot) (- 2 cot (x)) = 2

m^{2} - 20 m + 100 = 0

0 = - \frac{( x - 2 ) ^{2}}{8} + 8

What are the solutions to the equation 4w^2-20w=0 ?
The solutions to the equation 4w^2-20w=0 are w=5,w=0
Find the zeros of 4w^2-20w=0
The zeros of 4w^2-20w=0 are w=5,w=0