What are the solutions to the equation x^2+22x=-85 ?

The solutions to the equation x^2+22x=-85 are x=-5,x=-17

Find the zeros of x^2+22x=-85

The zeros of x^2+22x=-85 are x=-5,x=-17

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x^{2} + 22 x = - 85

x = - 5, x = - 17

Solution steps

x^{2} + 22 x = - 85

Move

85

to the left side

x^{2} + 22 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot 85}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot 85 = 12

x_{1, 2} = \frac{- 22 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 12}{2 \cdot 1}, x_{2} = \frac{- 22 - 12}{2 \cdot 1}

x = \frac{- 22 + 12}{2 \cdot 1} : - 5

x = \frac{- 22 - 12}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = - 5, x = - 17

(x - 12)^{2} = 625

x, 2 cos (x) - sin (x \cdot) (- 2 cot (x)) = 2

m^{2} - 20 m + 100 = 0

0 = - \frac{( x - 2 ) ^{2}}{8} + 8

12 x^{2} - 240 x + 875 = 0

What are the solutions to the equation x^2+22x=-85 ?
The solutions to the equation x^2+22x=-85 are x=-5,x=-17
Find the zeros of x^2+22x=-85
The zeros of x^2+22x=-85 are x=-5,x=-17