What are the solutions to the equation 12x^2-240x+875=0 ?

The solutions to the equation 12x^2-240x+875=0 are x=(5(12+sqrt(39)))/6 ,x=(5(12-sqrt(39)))/6

Find the zeros of 12x^2-240x+875=0

The zeros of 12x^2-240x+875=0 are x=(5(12+sqrt(39)))/6 ,x=(5(12-sqrt(39)))/6

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12 x^{2} - 240 x + 875 = 0

x = \frac{5 ( 12 + 39 )}{6}, x = \frac{5 ( 12 - 39 )}{6}

Decimal Notation

x = 15.20416 \dots, x = 4.79583 \dots

Solution steps

12 x^{2} - 240 x + 875 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 240 ) \pm ( - 240 ) ^{2} - 4 \cdot 12 \cdot 875}{2 \cdot 12}

(- 240)^{2} - 4 \cdot 12 \cdot 875 = 2039

x_{1, 2} = \frac{- ( - 240 ) \pm 20 39}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 240 ) + 20 39}{2 \cdot 12}, x_{2} = \frac{- ( - 240 ) - 20 39}{2 \cdot 12}

x = \frac{- ( - 240 ) + 20 39}{2 \cdot 12} : \frac{5 ( 12 + 39 )}{6}

x = \frac{- ( - 240 ) - 20 39}{2 \cdot 12} : \frac{5 ( 12 - 39 )}{6}

The solutions to the quadratic equation are:

x = \frac{5 ( 12 + 39 )}{6}, x = \frac{5 ( 12 - 39 )}{6}

5 m^{2} + 8 m = - 1

12 x^{2} - 288 = 0

- 0.05 x^{2} + 700 = 10 x + 220

(x + 3) (x - 4) = 3 x

x^{1 + l o g_{x} (64)} = 8 x^{2}

What are the solutions to the equation 12x^2-240x+875=0 ?
The solutions to the equation 12x^2-240x+875=0 are x=(5(12+sqrt(39)))/6 ,x=(5(12-sqrt(39)))/6
Find the zeros of 12x^2-240x+875=0
The zeros of 12x^2-240x+875=0 are x=(5(12+sqrt(39)))/6 ,x=(5(12-sqrt(39)))/6