What are the solutions to the equation -0.05x^2+700=10x+220 ?

The solutions to the equation -0.05x^2+700=10x+220 are x=-240,x=40

Find the zeros of -0.05x^2+700=10x+220

The zeros of -0.05x^2+700=10x+220 are x=-240,x=40

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- 0.05 x^{2} + 700 = 10 x + 220

x = - 240, x = 40

Solution steps

- 0.05 x^{2} + 700 = 10 x + 220

Multiply both sides by

100

- 5 x^{2} + 70000 = 1000 x + 22000

Move

22000

to the left side

- 5 x^{2} + 48000 = 1000 x

Move

1000 x

to the left side

- 5 x^{2} + 48000 - 1000 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} - 1000 x + 48000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1000 ) \pm ( - 1000 ) ^{2} - 4 ( - 5 ) \cdot 48000}{2 ( - 5 )}

(- 1000)^{2} - 4 (- 5) \cdot 48000 = 1400

x_{1, 2} = \frac{- ( - 1000 ) \pm 1400}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 1000 ) + 1400}{2 ( - 5 )}, x_{2} = \frac{- ( - 1000 ) - 1400}{2 ( - 5 )}

x = \frac{- ( - 1000 ) + 1400}{2 ( - 5 )} : - 240

x = \frac{- ( - 1000 ) - 1400}{2 ( - 5 )} : 40

The solutions to the quadratic equation are:

x = - 240, x = 40

(x + 3) (x - 4) = 3 x

x^{1 + l o g_{x} (64)} = 8 x^{2}

10 x^{2} + 34 x + 12 = 0

x, z = 49 - x^{2} - y^{2}

- 3 x^{2} + 8 = 2 x

What are the solutions to the equation -0.05x^2+700=10x+220 ?
The solutions to the equation -0.05x^2+700=10x+220 are x=-240,x=40
Find the zeros of -0.05x^2+700=10x+220
The zeros of -0.05x^2+700=10x+220 are x=-240,x=40