What are the solutions to the equation 16g^2+40g+25=0 ?

The solutions to the equation 16g^2+40g+25=0 are g=-5/4

Find the zeros of 16g^2+40g+25=0

The zeros of 16g^2+40g+25=0 are g=-5/4

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16 g^{2} + 40 g + 25 = 0

g = - \frac{5}{4}

Decimal Notation

g = - 1.25

Solution steps

16 g^{2} + 40 g + 25 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

4 0^{2} - 4 \cdot 16 \cdot 25 = 0

g_{1, 2} = \frac{- 40 \pm 0}{2 \cdot 16}

g = \frac{- 40}{2 \cdot 16}

\frac{- 40}{2 \cdot 16} = - \frac{5}{4}

g = - \frac{5}{4}

The solution to the quadratic equation is:

g = - \frac{5}{4}

8 x^{2} + 3 x = - 7

x^{2} = 0.81

x^{2} - 42 x + n = 0

\frac{1}{2} x^{2} - \frac{1}{4} x = 0

1 - (\frac{( 1 - 5 )}{2} x)^{2} - x^{2} = 0

What are the solutions to the equation 16g^2+40g+25=0 ?
The solutions to the equation 16g^2+40g+25=0 are g=-5/4
Find the zeros of 16g^2+40g+25=0
The zeros of 16g^2+40g+25=0 are g=-5/4