What are the solutions to the equation solvefor x,x^2-y^2=a ?

The solutions to the equation solvefor x,x^2-y^2=a are x=sqrt(a+y^2),x=-sqrt(a+y^2)

Find the zeros of solvefor x,x^2-y^2=a

The zeros of solvefor x,x^2-y^2=a are x=sqrt(a+y^2),x=-sqrt(a+y^2)

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solve for

x, x^{2} - y^{2} = a

x = a + y^{2}, x = - a + y^{2}

Solution steps

x^{2} - y^{2} = a

Move

y^{2}

to the right side

x^{2} = a + y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = a + y^{2}, x = - a + y^{2}

3 x^{2} + 12 x + 25 = 0

w^{2} + 10 w - 3 = 0

x, x^{2} + x - 5 = 0

x^{2} + 5 x - 14 = 0

(x + 3)^{2} - 9 = 0

What are the solutions to the equation solvefor x,x^2-y^2=a ?
The solutions to the equation solvefor x,x^2-y^2=a are x=sqrt(a+y^2),x=-sqrt(a+y^2)
Find the zeros of solvefor x,x^2-y^2=a
The zeros of solvefor x,x^2-y^2=a are x=sqrt(a+y^2),x=-sqrt(a+y^2)