What are the solutions to the equation w^2+10w-3=0 ?

The solutions to the equation w^2+10w-3=0 are w=-5+2sqrt(7),w=-5-2sqrt(7)

Find the zeros of w^2+10w-3=0

The zeros of w^2+10w-3=0 are w=-5+2sqrt(7),w=-5-2sqrt(7)

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w^{2} + 10 w - 3 = 0

w = - 5 + 27, w = - 5 - 27

Decimal Notation

w = 0.29150 \dots, w = - 10.29150 \dots

Solution steps

w^{2} + 10 w - 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 3) = 47

w_{1, 2} = \frac{- 10 \pm 4 7}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 10 + 4 7}{2 \cdot 1}, w_{2} = \frac{- 10 - 4 7}{2 \cdot 1}

w = \frac{- 10 + 4 7}{2 \cdot 1} : - 5 + 27

w = \frac{- 10 - 4 7}{2 \cdot 1} : - 5 - 27

The solutions to the quadratic equation are:

w = - 5 + 27, w = - 5 - 27

x, x^{2} + x - 5 = 0

x^{2} + 5 x - 14 = 0

(x + 3)^{2} - 9 = 0

2 s^{2} + 5 s + 6 = 0

- 5 x^{2} + 9 x + 3 = 0

What are the solutions to the equation w^2+10w-3=0 ?
The solutions to the equation w^2+10w-3=0 are w=-5+2sqrt(7),w=-5-2sqrt(7)
Find the zeros of w^2+10w-3=0
The zeros of w^2+10w-3=0 are w=-5+2sqrt(7),w=-5-2sqrt(7)