What are the solutions to the equation 4x(x-5)=0 ?

The solutions to the equation 4x(x-5)=0 are x=0,x=5

Find the zeros of 4x(x-5)=0

The zeros of 4x(x-5)=0 are x=0,x=5

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4 x (x - 5) = 0

x = 0, x = 5

Solution steps

4 x (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 5 = 0

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = 0, x = 5

a, (a + 2 d)^{2} = a^{2} + (a + d)^{2}

24 x^{2} + 128 x + 168 = 100 x^{2} + 40 x + 4

4 p^{2} - 78 = 11 p

4 x^{2} - 5 x - 6 = 0

x, x y - x^{2} + e^{y} = 5

What are the solutions to the equation 4x(x-5)=0 ?
The solutions to the equation 4x(x-5)=0 are x=0,x=5
Find the zeros of 4x(x-5)=0
The zeros of 4x(x-5)=0 are x=0,x=5