What are the solutions to the equation 4p^2-78=11p ?

The solutions to the equation 4p^2-78=11p are p=6,p=-13/4

Find the zeros of 4p^2-78=11p

The zeros of 4p^2-78=11p are p=6,p=-13/4

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4 p^{2} - 78 = 11 p

p = 6, p = - \frac{13}{4}

Decimal Notation

p = 6, p = - 3.25

Solution steps

4 p^{2} - 78 = 11 p

Move

11 p

to the left side

4 p^{2} - 78 - 11 p = 0

Write in the standard form

a x^{2} + b x + c = 0

4 p^{2} - 11 p - 78 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 ( - 78 )}{2 \cdot 4}

(- 11)^{2} - 4 \cdot 4 (- 78) = 37

p_{1, 2} = \frac{- ( - 11 ) \pm 37}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 11 ) + 37}{2 \cdot 4}, p_{2} = \frac{- ( - 11 ) - 37}{2 \cdot 4}

p = \frac{- ( - 11 ) + 37}{2 \cdot 4} : 6

p = \frac{- ( - 11 ) - 37}{2 \cdot 4} : - \frac{13}{4}

The solutions to the quadratic equation are:

p = 6, p = - \frac{13}{4}

4 x^{2} - 5 x - 6 = 0

x, x y - x^{2} + e^{y} = 5

3 x^{2} - 25 x + 8 = 0

x^{2} - 24 = 120

2 x^{2} + (6 \cdot 1 0^{- 5}) x - (7.2 \cdot 1 0^{- 9}) = 0

What are the solutions to the equation 4p^2-78=11p ?
The solutions to the equation 4p^2-78=11p are p=6,p=-13/4
Find the zeros of 4p^2-78=11p
The zeros of 4p^2-78=11p are p=6,p=-13/4