What are the solutions to the equation (k+2)(4k+2)=40 ?

The solutions to the equation (k+2)(4k+2)=40 are k=2,k=-9/2

Find the zeros of (k+2)(4k+2)=40

The zeros of (k+2)(4k+2)=40 are k=2,k=-9/2

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(k + 2) (4 k + 2) = 40

k = 2, k = - \frac{9}{2}

Decimal Notation

k = 2, k = - 4.5

Solution steps

(k + 2) (4 k + 2) = 40

Expand

(k + 2) (4 k + 2) : 4 k^{2} + 10 k + 4

4 k^{2} + 10 k + 4 = 40

Move

40

to the left side

4 k^{2} + 10 k - 36 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 4 ( - 36 )}{2 \cdot 4}

1 0^{2} - 4 \cdot 4 (- 36) = 26

k_{1, 2} = \frac{- 10 \pm 26}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- 10 + 26}{2 \cdot 4}, k_{2} = \frac{- 10 - 26}{2 \cdot 4}

k = \frac{- 10 + 26}{2 \cdot 4} : 2

k = \frac{- 10 - 26}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

k = 2, k = - \frac{9}{2}

10 - 12 x - 15 x^{2} = 4898.42 (\frac{x ^{2}}{0.00006})

(a - 5)^{2} = 32

(2 x + 1) (x + 8) = 0

3 x^{2} - 18 = - 6

9 y^{2} - 90 y + 8 = 0

What are the solutions to the equation (k+2)(4k+2)=40 ?
The solutions to the equation (k+2)(4k+2)=40 are k=2,k=-9/2
Find the zeros of (k+2)(4k+2)=40
The zeros of (k+2)(4k+2)=40 are k=2,k=-9/2