What are the solutions to the equation -6=-5x^2-13x ?

The solutions to the equation -6=-5x^2-13x are x=-3,x= 2/5

Find the zeros of -6=-5x^2-13x

The zeros of -6=-5x^2-13x are x=-3,x= 2/5

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- 6 = - 5 x^{2} - 13 x

x = - 3, x = \frac{2}{5}

Decimal Notation

x = - 3, x = 0.4

Solution steps

- 6 = - 5 x^{2} - 13 x

Switch sides

- 5 x^{2} - 13 x = - 6

Move

6

to the left side

- 5 x^{2} - 13 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 5 ) \cdot 6}{2 ( - 5 )}

(- 13)^{2} - 4 (- 5) \cdot 6 = 17

x_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 17}{2 ( - 5 )}, x_{2} = \frac{- ( - 13 ) - 17}{2 ( - 5 )}

x = \frac{- ( - 13 ) + 17}{2 ( - 5 )} : - 3

x = \frac{- ( - 13 ) - 17}{2 ( - 5 )} : \frac{2}{5}

The solutions to the quadratic equation are:

x = - 3, x = \frac{2}{5}

x^{2} + 10 x + 25 = 0

5 x^{2} + 6 x - 12 = 0

x^{2} - 6 x + 9 x = 0

\frac{- 1543}{120} = \frac{3}{5} x \frac{11}{4} (- \frac{11}{5} x \frac{8}{5})

- x^{2} + 1000 x = 0

What are the solutions to the equation -6=-5x^2-13x ?
The solutions to the equation -6=-5x^2-13x are x=-3,x= 2/5
Find the zeros of -6=-5x^2-13x
The zeros of -6=-5x^2-13x are x=-3,x= 2/5