What are the solutions to the equation -x^2+1000x=0 ?

The solutions to the equation -x^2+1000x=0 are x=0,x=1000

Find the zeros of -x^2+1000x=0

The zeros of -x^2+1000x=0 are x=0,x=1000

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- x^{2} + 1000 x = 0

x = 0, x = 1000

Solution steps

- x^{2} + 1000 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1000 \pm 100 0 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

100 0^{2} - 4 (- 1) \cdot 0 = 1000

x_{1, 2} = \frac{- 1000 \pm 1000}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1000 + 1000}{2 ( - 1 )}, x_{2} = \frac{- 1000 - 1000}{2 ( - 1 )}

x = \frac{- 1000 + 1000}{2 ( - 1 )} : 0

x = \frac{- 1000 - 1000}{2 ( - 1 )} : 1000

The solutions to the quadratic equation are:

x = 0, x = 1000

6 = x^{2} - 5 x + 42

24 x^{2} - 8 = 4 x

(x) (x - 5) = 234

13500 x^{2} + 52000000 x + 33000 = 0

x, (\frac{2 x - y}{2})^{2} + (\frac{y + 3 x}{3})^{2} = 1

What are the solutions to the equation -x^2+1000x=0 ?
The solutions to the equation -x^2+1000x=0 are x=0,x=1000
Find the zeros of -x^2+1000x=0
The zeros of -x^2+1000x=0 are x=0,x=1000