What are the solutions to the equation -32=8y^2 ?

The solutions to the equation -32=8y^2 are y=2i,y=-2i

Find the zeros of -32=8y^2

The zeros of -32=8y^2 are y=2i,y=-2i

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- 32 = 8 y^{2}

y = 2 i, y = - 2 i

Solution steps

- 32 = 8 y^{2}

Switch sides

8 y^{2} = - 32

Divide both sides by

8

y^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 4, y = - - 4

- 4 = 2 i

- - 4 = - 2 i

y = 2 i, y = - 2 i

3 (x + 7)^{2} + 17 = 59

- 4.19 x^{2} + 2 = 0

x, x^{2} - 6 x - 34 = 0

2.9 3^{2} = 19.8 2^{2} + (24 x)^{2} + (\frac{10}{π} x)^{2}

2 x^{2} - 3 = 1 - 2 x + 2

What are the solutions to the equation -32=8y^2 ?
The solutions to the equation -32=8y^2 are y=2i,y=-2i
Find the zeros of -32=8y^2
The zeros of -32=8y^2 are y=2i,y=-2i