What are the solutions to the equation 3(x+7)^2+17=59 ?

The solutions to the equation 3(x+7)^2+17=59 are x=sqrt(14)-7,x=-sqrt(14)-7

Find the zeros of 3(x+7)^2+17=59

The zeros of 3(x+7)^2+17=59 are x=sqrt(14)-7,x=-sqrt(14)-7

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3 (x + 7)^{2} + 17 = 59

x = 14 - 7, x = - 14 - 7

Decimal Notation

x = - 3.25834 \dots, x = - 10.74165 \dots

Solution steps

3 (x + 7)^{2} + 17 = 59

Move

17

to the right side

3 (x + 7)^{2} = 42

Divide both sides by

3

(x + 7)^{2} = 14

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 14 : x = 14 - 7

Solve

x + 7 = - 14 : x = - 14 - 7

The solutions to the quadratic equation are:

x = 14 - 7, x = - 14 - 7

- 4.19 x^{2} + 2 = 0

x, x^{2} - 6 x - 34 = 0

2.9 3^{2} = 19.8 2^{2} + (24 x)^{2} + (\frac{10}{π} x)^{2}

2 x^{2} - 3 = 1 - 2 x + 2

x, x^{2} - 2 x = 1

What are the solutions to the equation 3(x+7)^2+17=59 ?
The solutions to the equation 3(x+7)^2+17=59 are x=sqrt(14)-7,x=-sqrt(14)-7
Find the zeros of 3(x+7)^2+17=59
The zeros of 3(x+7)^2+17=59 are x=sqrt(14)-7,x=-sqrt(14)-7