What are the solutions to the equation solvefor x,x^2-2x=1 ?

The solutions to the equation solvefor x,x^2-2x=1 are x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of solvefor x,x^2-2x=1

The zeros of solvefor x,x^2-2x=1 are x=1+sqrt(2),x=1-sqrt(2)

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x, x^{2} - 2 x = 1

x = 1 + 2, x = 1 - 2

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

x^{2} - 2 x = 1

Move

1

to the left side

x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2}{2 \cdot 1} : 1 + 2

x = \frac{- ( - 2 ) - 2 2}{2 \cdot 1} : 1 - 2

The solutions to the quadratic equation are:

x = 1 + 2, x = 1 - 2

5 x^{2} + 100 x = 0

4 = x^{1} \cdot 4.55 + x^{2} \cdot 3.72

9 x^{2} - 5 x + 4 = 0

- 2 - 5 c^{2} = - 92

c^{2} = - 10 c

What are the solutions to the equation solvefor x,x^2-2x=1 ?
The solutions to the equation solvefor x,x^2-2x=1 are x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of solvefor x,x^2-2x=1
The zeros of solvefor x,x^2-2x=1 are x=1+sqrt(2),x=1-sqrt(2)