What are the solutions to the equation 2v^2+v+1=0 ?

The solutions to the equation 2v^2+v+1=0 are v=-1/4+i(sqrt(7))/4 ,v=-1/4-i(sqrt(7))/4

Find the zeros of 2v^2+v+1=0

The zeros of 2v^2+v+1=0 are v=-1/4+i(sqrt(7))/4 ,v=-1/4-i(sqrt(7))/4

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2 v^{2} + v + 1 = 0

v = - \frac{1}{4} + i \frac{7}{4}, v = - \frac{1}{4} - i \frac{7}{4}

Solution steps

2 v^{2} + v + 1 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 1 : 7 i

v_{1, 2} = \frac{- 1 \pm 7 i}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- 1 + 7 i}{2 \cdot 2}, v_{2} = \frac{- 1 - 7 i}{2 \cdot 2}

v = \frac{- 1 + 7 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{7}{4}

v = \frac{- 1 - 7 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

v = - \frac{1}{4} + i \frac{7}{4}, v = - \frac{1}{4} - i \frac{7}{4}

3 c^{2} - 13 c + 4 = - 4

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x^{2} + 2 x - 9 = 15

- 1 + \frac{( 60 - x ) ^{2}}{1200} = 0, x

3 x^{2} - 100 x + 460 = 0

What are the solutions to the equation 2v^2+v+1=0 ?
The solutions to the equation 2v^2+v+1=0 are v=-1/4+i(sqrt(7))/4 ,v=-1/4-i(sqrt(7))/4
Find the zeros of 2v^2+v+1=0
The zeros of 2v^2+v+1=0 are v=-1/4+i(sqrt(7))/4 ,v=-1/4-i(sqrt(7))/4