What are the solutions to the equation 0.4x^2+5.1x-6=0 ?

The solutions to the equation 0.4x^2+5.1x-6=0 are x=(-51+sqrt(3561))/8 ,x=(-51-sqrt(3561))/8

Find the zeros of 0.4x^2+5.1x-6=0

The zeros of 0.4x^2+5.1x-6=0 are x=(-51+sqrt(3561))/8 ,x=(-51-sqrt(3561))/8

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0.4 x^{2} + 5.1 x - 6 = 0

x = \frac{- 51 + 3561}{8}, x = \frac{- 51 - 3561}{8}

Decimal Notation

x = 1.08426 \dots, x = - 13.83426 \dots

Solution steps

0.4 x^{2} + 5.1 x - 6 = 0

Multiply both sides by

10

4 x^{2} + 51 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 51 \pm 5 1 ^{2} - 4 \cdot 4 ( - 60 )}{2 \cdot 4}

5 1^{2} - 4 \cdot 4 (- 60) = 3561

x_{1, 2} = \frac{- 51 \pm 3561}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 51 + 3561}{2 \cdot 4}, x_{2} = \frac{- 51 - 3561}{2 \cdot 4}

x = \frac{- 51 + 3561}{2 \cdot 4} : \frac{- 51 + 3561}{8}

x = \frac{- 51 - 3561}{2 \cdot 4} : \frac{- 51 - 3561}{8}

The solutions to the quadratic equation are:

x = \frac{- 51 + 3561}{8}, x = \frac{- 51 - 3561}{8}

x^{2} = 24

x^{2} = 25

x^{2} + (x - 6)^{2} = (x + 6)^{2}

x, x^{2} + (y - 1)^{2} + z^{2} = 4

x^{2} - 45 x + 500 = 0

What are the solutions to the equation 0.4x^2+5.1x-6=0 ?
The solutions to the equation 0.4x^2+5.1x-6=0 are x=(-51+sqrt(3561))/8 ,x=(-51-sqrt(3561))/8
Find the zeros of 0.4x^2+5.1x-6=0
The zeros of 0.4x^2+5.1x-6=0 are x=(-51+sqrt(3561))/8 ,x=(-51-sqrt(3561))/8