What are the solutions to the equation x^2-45x+500=0 ?

The solutions to the equation x^2-45x+500=0 are x=25,x=20

Find the zeros of x^2-45x+500=0

The zeros of x^2-45x+500=0 are x=25,x=20

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x^{2} - 45 x + 500 = 0

x = 25, x = 20

Solution steps

x^{2} - 45 x + 500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 45 ) \pm ( - 45 ) ^{2} - 4 \cdot 1 \cdot 500}{2 \cdot 1}

(- 45)^{2} - 4 \cdot 1 \cdot 500 = 5

x_{1, 2} = \frac{- ( - 45 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 45 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 45 ) - 5}{2 \cdot 1}

x = \frac{- ( - 45 ) + 5}{2 \cdot 1} : 25

x = \frac{- ( - 45 ) - 5}{2 \cdot 1} : 20

The solutions to the quadratic equation are:

x = 25, x = 20

x^{2} - 11 x + 24 = 0

25 x^{2} = 40 x - 16

38^{2} + 26^{2} = c^{2}

x, 3 x^{2} - 4 x + 3 = 0

2 x^{2} - 5 x - 2 = - 4 x + 1

What are the solutions to the equation x^2-45x+500=0 ?
The solutions to the equation x^2-45x+500=0 are x=25,x=20
Find the zeros of x^2-45x+500=0
The zeros of x^2-45x+500=0 are x=25,x=20