What are the solutions to the equation 2x^2-5x-2=-4x+1 ?

The solutions to the equation 2x^2-5x-2=-4x+1 are x= 3/2 ,x=-1

Find the zeros of 2x^2-5x-2=-4x+1

The zeros of 2x^2-5x-2=-4x+1 are x= 3/2 ,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 5 x - 2 = - 4 x + 1

x = \frac{3}{2}, x = - 1

Decimal Notation

x = 1.5, x = - 1

Solution steps

2 x^{2} - 5 x - 2 = - 4 x + 1

Move

1

to the left side

2 x^{2} - 5 x - 3 = - 4 x

Move

4 x

to the left side

2 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 2}

x = \frac{- ( - 1 ) + 5}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

x^{2} + 4 x = 1

2 x + 5 x^{2} = 1

(x + 3)^{2} = 3 (2 x + 3)

11.2 x^{2} = 392

3 x^{2} - 14 x - 14 = 0

What are the solutions to the equation 2x^2-5x-2=-4x+1 ?
The solutions to the equation 2x^2-5x-2=-4x+1 are x= 3/2 ,x=-1
Find the zeros of 2x^2-5x-2=-4x+1
The zeros of 2x^2-5x-2=-4x+1 are x= 3/2 ,x=-1