What are the solutions to the equation x^2-17x+10=0 ?

The solutions to the equation x^2-17x+10=0 are x=(17+sqrt(249))/2 ,x=(17-sqrt(249))/2

Find the zeros of x^2-17x+10=0

The zeros of x^2-17x+10=0 are x=(17+sqrt(249))/2 ,x=(17-sqrt(249))/2

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x^{2} - 17 x + 10 = 0

x = \frac{17 + 249}{2}, x = \frac{17 - 249}{2}

Decimal Notation

x = 16.38986 \dots, x = 0.61013 \dots

Solution steps

x^{2} - 17 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 10 = 249

x_{1, 2} = \frac{- ( - 17 ) \pm 249}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 249}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 249}{2 \cdot 1}

x = \frac{- ( - 17 ) + 249}{2 \cdot 1} : \frac{17 + 249}{2}

x = \frac{- ( - 17 ) - 249}{2 \cdot 1} : \frac{17 - 249}{2}

The solutions to the quadratic equation are:

x = \frac{17 + 249}{2}, x = \frac{17 - 249}{2}

3 x^{(2)} + 2 x - 6 = 0

0 = - 3 x^{2} + 9 x + 30

49 x^{2} + 9 x = 0

x, 13 x^{2} + 23 x y + 15 y^{2} - 48 = 0

0 = - 0.2 q^{2} + 250 q - 75000

What are the solutions to the equation x^2-17x+10=0 ?
The solutions to the equation x^2-17x+10=0 are x=(17+sqrt(249))/2 ,x=(17-sqrt(249))/2
Find the zeros of x^2-17x+10=0
The zeros of x^2-17x+10=0 are x=(17+sqrt(249))/2 ,x=(17-sqrt(249))/2