What are the solutions to the equation 0=-0.2q^2+250q-75000 ?

The solutions to the equation 0=-0.2q^2+250q-75000 are q=500,q=750

Find the zeros of 0=-0.2q^2+250q-75000

The zeros of 0=-0.2q^2+250q-75000 are q=500,q=750

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0 = - 0.2 q^{2} + 250 q - 75000

q = 500, q = 750

Solution steps

0 = - 0.2 q^{2} + 250 q - 75000

Multiply both sides by

10

0 = - 2 q^{2} + 2500 q - 750000

Switch sides

- 2 q^{2} + 2500 q - 750000 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 2500 \pm 250 0 ^{2} - 4 ( - 2 ) ( - 750000 )}{2 ( - 2 )}

250 0^{2} - 4 (- 2) (- 750000) = 500

q_{1, 2} = \frac{- 2500 \pm 500}{2 ( - 2 )}

Separate the solutions

q_{1} = \frac{- 2500 + 500}{2 ( - 2 )}, q_{2} = \frac{- 2500 - 500}{2 ( - 2 )}

q = \frac{- 2500 + 500}{2 ( - 2 )} : 500

q = \frac{- 2500 - 500}{2 ( - 2 )} : 750

The solutions to the quadratic equation are:

q = 500, q = 750

x^{2} + 16 x - 63 = 0

3 c^{2} - 3 = 1

x^{2} - 2 x - 3 = - 5

x - x^{2} - 1 = 0

5 p^{2} - p - 44 = 0

What are the solutions to the equation 0=-0.2q^2+250q-75000 ?
The solutions to the equation 0=-0.2q^2+250q-75000 are q=500,q=750
Find the zeros of 0=-0.2q^2+250q-75000
The zeros of 0=-0.2q^2+250q-75000 are q=500,q=750