What are the solutions to the equation x^2+16x-63=0 ?

The solutions to the equation x^2+16x-63=0 are x=-8+sqrt(127),x=-8-sqrt(127)

Find the zeros of x^2+16x-63=0

The zeros of x^2+16x-63=0 are x=-8+sqrt(127),x=-8-sqrt(127)

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x^{2} + 16 x - 63 = 0

x = - 8 + 127, x = - 8 - 127

Decimal Notation

x = 3.26942 \dots, x = - 19.26942 \dots

Solution steps

x^{2} + 16 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 63) = 2127

x_{1, 2} = \frac{- 16 \pm 2 127}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 127}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 127}{2 \cdot 1}

x = \frac{- 16 + 2 127}{2 \cdot 1} : - 8 + 127

x = \frac{- 16 - 2 127}{2 \cdot 1} : - 8 - 127

The solutions to the quadratic equation are:

x = - 8 + 127, x = - 8 - 127

3 c^{2} - 3 = 1

x^{2} - 2 x - 3 = - 5

x - x^{2} - 1 = 0

5 p^{2} - p - 44 = 0

16 v^{2} - 40 v + 31 = 6

What are the solutions to the equation x^2+16x-63=0 ?
The solutions to the equation x^2+16x-63=0 are x=-8+sqrt(127),x=-8-sqrt(127)
Find the zeros of x^2+16x-63=0
The zeros of x^2+16x-63=0 are x=-8+sqrt(127),x=-8-sqrt(127)