What are the solutions to the equation x^2-4=0 ?

The solutions to the equation x^2-4=0 are x=2,x=-2

Find the zeros of x^2-4=0

The zeros of x^2-4=0 are x=2,x=-2

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x^{2} - 4 = 0

x = 2, x = - 2

Solution steps

x^{2} - 4 = 0

Move

4

to the right side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

\frac{15}{48} \div (\frac{3}{8} - \frac{7}{12})

- \frac{3}{4} + \frac{7}{2}

8 y - y = 7

11 a - 8 a + 8 - 5 = 5 a - 3 - 6

x (3 x + 2) \leq (x + 2)^{2}

What are the solutions to the equation x^2-4=0 ?
The solutions to the equation x^2-4=0 are x=2,x=-2
Find the zeros of x^2-4=0
The zeros of x^2-4=0 are x=2,x=-2