What are the solutions to the equation -2x=5+2x+3x^2 ?

The solutions to the equation -2x=5+2x+3x^2 are x=-2/3+i(sqrt(11))/3 ,x=-2/3-i(sqrt(11))/3

Find the zeros of -2x=5+2x+3x^2

The zeros of -2x=5+2x+3x^2 are x=-2/3+i(sqrt(11))/3 ,x=-2/3-i(sqrt(11))/3

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- 2 x = 5 + 2 x + 3 x^{2}

x = - \frac{2}{3} + i \frac{11}{3}, x = - \frac{2}{3} - i \frac{11}{3}

Solution steps

- 2 x = 5 + 2 x + 3 x^{2}

Switch sides

5 + 2 x + 3 x^{2} = - 2 x

Move

2 x

to the left side

3 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

4^{2} - 4 \cdot 3 \cdot 5 : 211 i

x_{1, 2} = \frac{- 4 \pm 2 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 11 i}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 11 i}{2 \cdot 3}

x = \frac{- 4 + 2 11 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{11}{3}

x = \frac{- 4 - 2 11 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3} + i \frac{11}{3}, x = - \frac{2}{3} - i \frac{11}{3}

28090 = 25000 (1 + \frac{r}{100})^{2}

(x + 4)^{2} = 361

3 x^{2} + 5 = 16 x

4 x^{2} + 1 = 8 x - 2

200 - 2 x = 100 + 0.2 \cdot x^{2}

What are the solutions to the equation -2x=5+2x+3x^2 ?
The solutions to the equation -2x=5+2x+3x^2 are x=-2/3+i(sqrt(11))/3 ,x=-2/3-i(sqrt(11))/3
Find the zeros of -2x=5+2x+3x^2
The zeros of -2x=5+2x+3x^2 are x=-2/3+i(sqrt(11))/3 ,x=-2/3-i(sqrt(11))/3