What are the solutions to the equation solvefor x,f=px^2-4 ?

The solutions to the equation solvefor x,f=px^2-4 are x=sqrt((f+4)/p),x=-sqrt((f+4)/p);\quad p\ne 0

Find the zeros of solvefor x,f=px^2-4

The zeros of solvefor x,f=px^2-4 are x=sqrt((f+4)/p),x=-sqrt((f+4)/p);\quad p\ne 0

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solve for

x, f = p x^{2} - 4

x = \frac{f + 4}{p}, x = - \frac{f + 4}{p}; p \neq = 0

Solution steps

f = p x^{2} - 4

Switch sides

p x^{2} - 4 = f

Move

4

to the right side

p x^{2} = f + 4

Divide both sides by

p; p \neq = 0

x^{2} = \frac{f + 4}{p}; p \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{f + 4}{p}, x = - \frac{f + 4}{p}; p \neq = 0

2 x^{2} - 10 x + 15 = 0

x^{2} + 6 x - 7 = 0

x, (x - a)^{2} + y^{2} = b

x, y^{3} - 2 x^{2} = 1388

(m^{2} - n^{2}) x^{2} - 4 mn x = m^{2} - n^{2}

What are the solutions to the equation solvefor x,f=px^2-4 ?
The solutions to the equation solvefor x,f=px^2-4 are x=sqrt((f+4)/p),x=-sqrt((f+4)/p);\quad p\ne 0
Find the zeros of solvefor x,f=px^2-4
The zeros of solvefor x,f=px^2-4 are x=sqrt((f+4)/p),x=-sqrt((f+4)/p);\quad p\ne 0