What are the solutions to the equation (1/3)*x^2+3=0 ?

The solutions to the equation (1/3)*x^2+3=0 are x=3i,x=-3i

Find the zeros of (1/3)*x^2+3=0

The zeros of (1/3)*x^2+3=0 are x=3i,x=-3i

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(\frac{1}{3}) \cdot x^{2} + 3 = 0

x = 3 i, x = - 3 i

Solution steps

(\frac{1}{3}) x^{2} + 3 = 0

Refine

\frac{1}{3} x^{2} + 3 = 0

Move

3

to the right side

\frac{1}{3} x^{2} = - 3

Multiply both sides by

3

x^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9, x = - - 9

- 9 = 3 i

- - 9 = - 3 i

x = 3 i, x = - 3 i

(3 x - 8)^{2} = - 50

x^{2} + 1 2^{2} = 1 6^{2}

z^{2} + 2 z + 17 = 0

x, x^{2} + y^{2} + z^{2} = 4 x

x, x^{2} + y^{2} - z = 0

What are the solutions to the equation (1/3)*x^2+3=0 ?
The solutions to the equation (1/3)*x^2+3=0 are x=3i,x=-3i
Find the zeros of (1/3)*x^2+3=0
The zeros of (1/3)*x^2+3=0 are x=3i,x=-3i