What are the solutions to the equation x^2-2x-x/2 =0 ?

The solutions to the equation x^2-2x-x/2 =0 are x= 5/2 ,x=0

Find the zeros of x^2-2x-x/2 =0

The zeros of x^2-2x-x/2 =0 are x= 5/2 ,x=0

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x^{2} - 2 x - \frac{x}{2} = 0

x = \frac{5}{2}, x = 0

Decimal Notation

x = 2.5, x = 0

Solution steps

x^{2} - 2 x - \frac{x}{2} = 0

Multiply both sides by

2

2 x^{2} - 4 x - x = 0

2 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 2}

x = \frac{- ( - 5 ) + 5}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 5 ) - 5}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 0

\frac{1}{20} x^{2} + 3 x + 50 = 0

(x - 3) (2 x - 1) + (x - 3) (- x + 5) = 0

3 \cdot (x + 2) \cdot (x - 2) = (x - 4)^{2} + 8 x

x^{2} - x + 400 = 0

(4 x + 48)^{2} = (2 x + 64)^{2}

What are the solutions to the equation x^2-2x-x/2 =0 ?
The solutions to the equation x^2-2x-x/2 =0 are x= 5/2 ,x=0
Find the zeros of x^2-2x-x/2 =0
The zeros of x^2-2x-x/2 =0 are x= 5/2 ,x=0