What are the solutions to the equation 1/20 x^2+3x+50=0 ?

The solutions to the equation 1/20 x^2+3x+50=0 are x=-30+10i,x=-30-10i

Find the zeros of 1/20 x^2+3x+50=0

The zeros of 1/20 x^2+3x+50=0 are x=-30+10i,x=-30-10i

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\frac{1}{20} x^{2} + 3 x + 50 = 0

x = - 30 + 10 i, x = - 30 - 10 i

Solution steps

\frac{1}{20} x^{2} + 3 x + 50 = 0

Multiply both sides by

20

x^{2} + 60 x + 1000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 1 \cdot 1000}{2 \cdot 1}

Simplify

6 0^{2} - 4 \cdot 1 \cdot 1000 : 20 i

x_{1, 2} = \frac{- 60 \pm 20 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 60 + 20 i}{2 \cdot 1}, x_{2} = \frac{- 60 - 20 i}{2 \cdot 1}

x = \frac{- 60 + 20 i}{2 \cdot 1} : - 30 + 10 i

x = \frac{- 60 - 20 i}{2 \cdot 1} : - 30 - 10 i

The solutions to the quadratic equation are:

x = - 30 + 10 i, x = - 30 - 10 i

(x - 3) (2 x - 1) + (x - 3) (- x + 5) = 0

3 \cdot (x + 2) \cdot (x - 2) = (x - 4)^{2} + 8 x

x^{2} - x + 400 = 0

(4 x + 48)^{2} = (2 x + 64)^{2}

y^{2} - 15 y + 56 = 0

What are the solutions to the equation 1/20 x^2+3x+50=0 ?
The solutions to the equation 1/20 x^2+3x+50=0 are x=-30+10i,x=-30-10i
Find the zeros of 1/20 x^2+3x+50=0
The zeros of 1/20 x^2+3x+50=0 are x=-30+10i,x=-30-10i