What are the solutions to the equation r^2+z^2=1 ?

The solutions to the equation r^2+z^2=1 are z=sqrt(1-r^2),z=-sqrt(1-r^2)

Find the zeros of r^2+z^2=1

The zeros of r^2+z^2=1 are z=sqrt(1-r^2),z=-sqrt(1-r^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + z^{2} = 1

z = 1 - r^{2}, z = - 1 - r^{2}

Solution steps

r^{2} + z^{2} = 1

Move

r^{2}

to the right side

z^{2} = 1 - r^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 1 - r^{2}, z = - 1 - r^{2}

(x + 4)^{2} + 7 (x + 4) + 10 = 0

x^{2} - 18 x + 73 = 0

25 x^{2} - 15 x = 0

x^{2} - 10 x + 15 = 0

- x^{2} + 11 x - 28 = 0

What are the solutions to the equation r^2+z^2=1 ?
The solutions to the equation r^2+z^2=1 are z=sqrt(1-r^2),z=-sqrt(1-r^2)
Find the zeros of r^2+z^2=1
The zeros of r^2+z^2=1 are z=sqrt(1-r^2),z=-sqrt(1-r^2)