What are the solutions to the equation s^2+40s+400=0 ?

The solutions to the equation s^2+40s+400=0 are s=-20

Find the zeros of s^2+40s+400=0

The zeros of s^2+40s+400=0 are s=-20

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s^{2} + 40 s + 400 = 0

s = - 20

Solution steps

s^{2} + 40 s + 400 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot 400}{2 \cdot 1}

4 0^{2} - 4 \cdot 1 \cdot 400 = 0

s_{1, 2} = \frac{- 40 \pm 0}{2 \cdot 1}

s = \frac{- 40}{2 \cdot 1}

\frac{- 40}{2 \cdot 1} = - 20

s = - 20

The solution to the quadratic equation is:

s = - 20

- 5 (- x + 3) - 2 = \frac{1}{2} x (x + 2) - \frac{19}{2}

x, 2 x^{2} + 4 x - 3 = 0

x, r an g o^{4} y^{2} = x^{2} - 4 x

- 2 q^{2} + 60 q - 120 = 0

5 x^{2} - 3 x = 7

What are the solutions to the equation s^2+40s+400=0 ?
The solutions to the equation s^2+40s+400=0 are s=-20
Find the zeros of s^2+40s+400=0
The zeros of s^2+40s+400=0 are s=-20