What are the solutions to the equation -2q^2+60q-120=0 ?

The solutions to the equation -2q^2+60q-120=0 are q=15-sqrt(165),q=15+sqrt(165)

Find the zeros of -2q^2+60q-120=0

The zeros of -2q^2+60q-120=0 are q=15-sqrt(165),q=15+sqrt(165)

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- 2 q^{2} + 60 q - 120 = 0

q = 15 - 165, q = 15 + 165

Decimal Notation

q = 2.15476 \dots, q = 27.84523 \dots

Solution steps

- 2 q^{2} + 60 q - 120 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 2 ) ( - 120 )}{2 ( - 2 )}

6 0^{2} - 4 (- 2) (- 120) = 4165

q_{1, 2} = \frac{- 60 \pm 4 165}{2 ( - 2 )}

Separate the solutions

q_{1} = \frac{- 60 + 4 165}{2 ( - 2 )}, q_{2} = \frac{- 60 - 4 165}{2 ( - 2 )}

q = \frac{- 60 + 4 165}{2 ( - 2 )} : 15 - 165

q = \frac{- 60 - 4 165}{2 ( - 2 )} : 15 + 165

The solutions to the quadratic equation are:

q = 15 - 165, q = 15 + 165

5 x^{2} - 3 x = 7

3 y^{2} + 10 y - 8 = 0

(\frac{35}{6})^{2} + y^{2} = 1

80 x - 16 x^{2} = 0

3 (x + 4)^{2} - 24 = 0

What are the solutions to the equation -2q^2+60q-120=0 ?
The solutions to the equation -2q^2+60q-120=0 are q=15-sqrt(165),q=15+sqrt(165)
Find the zeros of -2q^2+60q-120=0
The zeros of -2q^2+60q-120=0 are q=15-sqrt(165),q=15+sqrt(165)