What are the solutions to the equation 3y^2+10y-8=0 ?

The solutions to the equation 3y^2+10y-8=0 are y= 2/3 ,y=-4

Find the zeros of 3y^2+10y-8=0

The zeros of 3y^2+10y-8=0 are y= 2/3 ,y=-4

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3 y^{2} + 10 y - 8 = 0

y = \frac{2}{3}, y = - 4

Decimal Notation

y = 0.66666 \dots, y = - 4

Solution steps

3 y^{2} + 10 y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 8) = 14

y_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 10 + 14}{2 \cdot 3}, y_{2} = \frac{- 10 - 14}{2 \cdot 3}

y = \frac{- 10 + 14}{2 \cdot 3} : \frac{2}{3}

y = \frac{- 10 - 14}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

y = \frac{2}{3}, y = - 4

(\frac{35}{6})^{2} + y^{2} = 1

80 x - 16 x^{2} = 0

3 (x + 4)^{2} - 24 = 0

3 x^{2} - 5 x - 2 = 0

8^{2} + x^{2} = 5^{2}

What are the solutions to the equation 3y^2+10y-8=0 ?
The solutions to the equation 3y^2+10y-8=0 are y= 2/3 ,y=-4
Find the zeros of 3y^2+10y-8=0
The zeros of 3y^2+10y-8=0 are y= 2/3 ,y=-4