What are the solutions to the equation 70x^2+120x=440 ?

The solutions to the equation 70x^2+120x=440 are x=(2(sqrt(86)-3))/7 ,x=-(2(3+sqrt(86)))/7

Find the zeros of 70x^2+120x=440

The zeros of 70x^2+120x=440 are x=(2(sqrt(86)-3))/7 ,x=-(2(3+sqrt(86)))/7

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70 x^{2} + 120 x = 440

x = \frac{2 ( 86 - 3 )}{7}, x = - \frac{2 ( 3 + 86 )}{7}

Decimal Notation

x = 1.79246 \dots, x = - 3.50674 \dots

Solution steps

70 x^{2} + 120 x = 440

Move

440

to the left side

70 x^{2} + 120 x - 440 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 \cdot 70 ( - 440 )}{2 \cdot 70}

12 0^{2} - 4 \cdot 70 (- 440) = 4086

x_{1, 2} = \frac{- 120 \pm 40 86}{2 \cdot 70}

Separate the solutions

x_{1} = \frac{- 120 + 40 86}{2 \cdot 70}, x_{2} = \frac{- 120 - 40 86}{2 \cdot 70}

x = \frac{- 120 + 40 86}{2 \cdot 70} : \frac{2 ( 86 - 3 )}{7}

x = \frac{- 120 - 40 86}{2 \cdot 70} : - \frac{2 ( 3 + 86 )}{7}

The solutions to the quadratic equation are:

x = \frac{2 ( 86 - 3 )}{7}, x = - \frac{2 ( 3 + 86 )}{7}

2 x^{2} - 14 x + 10 = 26

x^{2} - 14 x + 35 = - 10

v, E = m g h + \frac{1}{2} m v^{2}

x, x (y^{2} + 3) = (y^{2} x^{2}) + 3

2 x^{2} + 9 x + 10 = 0

What are the solutions to the equation 70x^2+120x=440 ?
The solutions to the equation 70x^2+120x=440 are x=(2(sqrt(86)-3))/7 ,x=-(2(3+sqrt(86)))/7
Find the zeros of 70x^2+120x=440
The zeros of 70x^2+120x=440 are x=(2(sqrt(86)-3))/7 ,x=-(2(3+sqrt(86)))/7