What are the solutions to the equation (x-3)^2-4=6 ?

The solutions to the equation (x-3)^2-4=6 are x=sqrt(10)+3,x=-sqrt(10)+3

Find the zeros of (x-3)^2-4=6

The zeros of (x-3)^2-4=6 are x=sqrt(10)+3,x=-sqrt(10)+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 3)^{2} - 4 = 6

x = 10 + 3, x = - 10 + 3

Decimal Notation

x = 6.16227 \dots, x = - 0.16227 \dots

Solution steps

(x - 3)^{2} - 4 = 6

Move

4

to the right side

(x - 3)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 10 : x = 10 + 3

Solve

x - 3 = - 10 : x = - 10 + 3

The solutions to the quadratic equation are:

x = 10 + 3, x = - 10 + 3

2 p^{2} - 5 p - 2 = - 3 p^{2}

\frac{x ^{2}}{3} - \frac{3 x}{4} = \frac{1 - x}{6}

1653.75 = 1500 (1 + 2 x + x^{2})

x, x^{2} + 5 y^{2} + e^{2 y} = 5

(x + 4)^{2} - 5 = 0

What are the solutions to the equation (x-3)^2-4=6 ?
The solutions to the equation (x-3)^2-4=6 are x=sqrt(10)+3,x=-sqrt(10)+3
Find the zeros of (x-3)^2-4=6
The zeros of (x-3)^2-4=6 are x=sqrt(10)+3,x=-sqrt(10)+3