What are the solutions to the equation (pix^2-22x^2+720x)/9 =0 ?

The solutions to the equation (pix^2-22x^2+720x)/9 =0 are x=0,x=-(720)/(pi-22)

Find the zeros of (pix^2-22x^2+720x)/9 =0

The zeros of (pix^2-22x^2+720x)/9 =0 are x=0,x=-(720)/(pi-22)

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\frac{π x ^{2} - 22 x ^{2} + 720 x}{9} = 0

x = 0, x = - \frac{720}{π - 22}

Decimal Notation

x = 0, x = 38.17925 \dots

Solution steps

\frac{π x ^{2} - 22 x ^{2} + 720 x}{9} = 0

Multiply both sides by

9

(π - 22) x^{2} + 720 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 720 \pm 72 0 ^{2} - 4 ( π - 22 ) \cdot 0}{2 ( π - 22 )}

72 0^{2} - 4 (π - 22) \cdot 0 = 720

x_{1, 2} = \frac{- 720 \pm 720}{2 ( π - 22 )}

Separate the solutions

x_{1} = \frac{- 720 + 720}{2 ( π - 22 )}, x_{2} = \frac{- 720 - 720}{2 ( π - 22 )}

x = \frac{- 720 + 720}{2 ( π - 22 )} : 0

x = \frac{- 720 - 720}{2 ( π - 22 )} : - \frac{720}{π - 22}

The solutions to the quadratic equation are:

x = 0, x = - \frac{720}{π - 22}

7 x^{2} - 70 x + 175 = 0

x^{2} + 4 x - 12 = 2

x^{2} - 3 x + 21 = 0

8 x^{2} + 10 x - 7 = 0

5 w^{2} - 11 w = 12

What are the solutions to the equation (pix^2-22x^2+720x)/9 =0 ?
The solutions to the equation (pix^2-22x^2+720x)/9 =0 are x=0,x=-(720)/(pi-22)
Find the zeros of (pix^2-22x^2+720x)/9 =0
The zeros of (pix^2-22x^2+720x)/9 =0 are x=0,x=-(720)/(pi-22)