What are the solutions to the equation -3x^2+9x+4=0 ?

The solutions to the equation -3x^2+9x+4=0 are x=-(-9+sqrt(129))/6 ,x=(9+sqrt(129))/6

Find the zeros of -3x^2+9x+4=0

The zeros of -3x^2+9x+4=0 are x=-(-9+sqrt(129))/6 ,x=(9+sqrt(129))/6

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- 3 x^{2} + 9 x + 4 = 0

x = - \frac{- 9 + 129}{6}, x = \frac{9 + 129}{6}

Decimal Notation

x = - 0.39296 \dots, x = 3.39296 \dots

Solution steps

- 3 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 3 ) \cdot 4}{2 ( - 3 )}

9^{2} - 4 (- 3) \cdot 4 = 129

x_{1, 2} = \frac{- 9 \pm 129}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 9 + 129}{2 ( - 3 )}, x_{2} = \frac{- 9 - 129}{2 ( - 3 )}

x = \frac{- 9 + 129}{2 ( - 3 )} : - \frac{- 9 + 129}{6}

x = \frac{- 9 - 129}{2 ( - 3 )} : \frac{9 + 129}{6}

The solutions to the quadratic equation are:

x = - \frac{- 9 + 129}{6}, x = \frac{9 + 129}{6}

4 x^{2} + 7 x - 20 = 0

x, x^{2} y^{2} + 2 x^{2} - 4 = 0

x, 36 x^{2} + 100 y^{2} + 225 z^{2} = 12600

n^{2} - 2 n - 48 = 0

12 m^{2} + 6 m = 0

What are the solutions to the equation -3x^2+9x+4=0 ?
The solutions to the equation -3x^2+9x+4=0 are x=-(-9+sqrt(129))/6 ,x=(9+sqrt(129))/6
Find the zeros of -3x^2+9x+4=0
The zeros of -3x^2+9x+4=0 are x=-(-9+sqrt(129))/6 ,x=(9+sqrt(129))/6