What are the solutions to the equation 3w^2+18w=0 ?

The solutions to the equation 3w^2+18w=0 are w=0,w=-6

Find the zeros of 3w^2+18w=0

The zeros of 3w^2+18w=0 are w=0,w=-6

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3 w^{2} + 18 w = 0

w = 0, w = - 6

Solution steps

3 w^{2} + 18 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 0 = 18

w_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- 18 + 18}{2 \cdot 3}, w_{2} = \frac{- 18 - 18}{2 \cdot 3}

w = \frac{- 18 + 18}{2 \cdot 3} : 0

w = \frac{- 18 - 18}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

w = 0, w = - 6

x, 16 \frac{x}{2} x = - \frac{1}{y}

- x^{2} + 14 = 10

x^{2} - 10 x - 19 = 0

(3 x - 5) (7 - 5 x) + (5 x + 2) (2 x - 2) - 2 = 0

y, 2 x = y^{2}

What are the solutions to the equation 3w^2+18w=0 ?
The solutions to the equation 3w^2+18w=0 are w=0,w=-6
Find the zeros of 3w^2+18w=0
The zeros of 3w^2+18w=0 are w=0,w=-6