What are the solutions to the equation x^2-300x+14400=0 ?

The solutions to the equation x^2-300x+14400=0 are x=240,x=60

Find the zeros of x^2-300x+14400=0

The zeros of x^2-300x+14400=0 are x=240,x=60

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x^{2} - 300 x + 14400 = 0

x = 240, x = 60

Solution steps

x^{2} - 300 x + 14400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 1 \cdot 14400}{2 \cdot 1}

(- 300)^{2} - 4 \cdot 1 \cdot 14400 = 180

x_{1, 2} = \frac{- ( - 300 ) \pm 180}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 300 ) + 180}{2 \cdot 1}, x_{2} = \frac{- ( - 300 ) - 180}{2 \cdot 1}

x = \frac{- ( - 300 ) + 180}{2 \cdot 1} : 240

x = \frac{- ( - 300 ) - 180}{2 \cdot 1} : 60

The solutions to the quadratic equation are:

x = 240, x = 60

9 x^{2} + 24 x + 20 = 4

(x^{2} - 25) = 0

x^{2} + 6 x + 11 = 3

y^{2} - 3 y + 10 = 0

2 x^{2} + 9 x + 3 = 8

What are the solutions to the equation x^2-300x+14400=0 ?
The solutions to the equation x^2-300x+14400=0 are x=240,x=60
Find the zeros of x^2-300x+14400=0
The zeros of x^2-300x+14400=0 are x=240,x=60