What are the solutions to the equation solvefor x,5x^2+7x-2=0 ?

The solutions to the equation solvefor x,5x^2+7x-2=0 are x=(-7+sqrt(89))/(10),x=(-7-sqrt(89))/(10)

Find the zeros of solvefor x,5x^2+7x-2=0

The zeros of solvefor x,5x^2+7x-2=0 are x=(-7+sqrt(89))/(10),x=(-7-sqrt(89))/(10)

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x, 5 x^{2} + 7 x - 2 = 0

x = \frac{- 7 + 89}{10}, x = \frac{- 7 - 89}{10}

Decimal Notation

x = 0.24339 \dots, x = - 1.64339 \dots

Solution steps

5 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 2) = 89

x_{1, 2} = \frac{- 7 \pm 89}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 89}{2 \cdot 5}, x_{2} = \frac{- 7 - 89}{2 \cdot 5}

x = \frac{- 7 + 89}{2 \cdot 5} : \frac{- 7 + 89}{10}

x = \frac{- 7 - 89}{2 \cdot 5} : \frac{- 7 - 89}{10}

The solutions to the quadratic equation are:

x = \frac{- 7 + 89}{10}, x = \frac{- 7 - 89}{10}

- 4.9 t^{2} + 2 = 0

2 x^{2} + 18 x + 33 = 0

w^{2} - 47 w = 0

(3 p + 2)^{2} = 12

r^{2} + 4 r + \frac{76}{3} = 0

What are the solutions to the equation solvefor x,5x^2+7x-2=0 ?
The solutions to the equation solvefor x,5x^2+7x-2=0 are x=(-7+sqrt(89))/(10),x=(-7-sqrt(89))/(10)
Find the zeros of solvefor x,5x^2+7x-2=0
The zeros of solvefor x,5x^2+7x-2=0 are x=(-7+sqrt(89))/(10),x=(-7-sqrt(89))/(10)