What are the solutions to the equation u^2+2u-6=0 ?

The solutions to the equation u^2+2u-6=0 are u=-1+sqrt(7),u=-1-sqrt(7)

Find the zeros of u^2+2u-6=0

The zeros of u^2+2u-6=0 are u=-1+sqrt(7),u=-1-sqrt(7)

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u^{2} + 2 u - 6 = 0

u = - 1 + 7, u = - 1 - 7

Decimal Notation

u = 1.64575 \dots, u = - 3.64575 \dots

Solution steps

u^{2} + 2 u - 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 6) = 27

u_{1, 2} = \frac{- 2 \pm 2 7}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 2 + 2 7}{2 \cdot 1}, u_{2} = \frac{- 2 - 2 7}{2 \cdot 1}

u = \frac{- 2 + 2 7}{2 \cdot 1} : - 1 + 7

u = \frac{- 2 - 2 7}{2 \cdot 1} : - 1 - 7

The solutions to the quadratic equation are:

u = - 1 + 7, u = - 1 - 7

x, 3 x^{2} - 12 m^{2} = 0

16 - x^{2} = x (8 + 2)

\frac{1}{3} x^{2} + \frac{123}{4} x - \frac{1}{6} = 0

x^{2} - 20 x + 116 = 0

r^{2} - 123 r + 80 = 0

What are the solutions to the equation u^2+2u-6=0 ?
The solutions to the equation u^2+2u-6=0 are u=-1+sqrt(7),u=-1-sqrt(7)
Find the zeros of u^2+2u-6=0
The zeros of u^2+2u-6=0 are u=-1+sqrt(7),u=-1-sqrt(7)