What are the solutions to the equation x^2-20x+116=0 ?

The solutions to the equation x^2-20x+116=0 are x=10+4i,x=10-4i

Find the zeros of x^2-20x+116=0

The zeros of x^2-20x+116=0 are x=10+4i,x=10-4i

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x^{2} - 20 x + 116 = 0

x = 10 + 4 i, x = 10 - 4 i

Solution steps

x^{2} - 20 x + 116 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 116}{2 \cdot 1}

Simplify

(- 20)^{2} - 4 \cdot 1 \cdot 116 : 8 i

x_{1, 2} = \frac{- ( - 20 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8 i}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 8 i}{2 \cdot 1}

x = \frac{- ( - 20 ) + 8 i}{2 \cdot 1} : 10 + 4 i

x = \frac{- ( - 20 ) - 8 i}{2 \cdot 1} : 10 - 4 i

The solutions to the quadratic equation are:

x = 10 + 4 i, x = 10 - 4 i

r^{2} - 123 r + 80 = 0

0 = x^{2} + 12 x + 20

\frac{1}{2} x + 2 = \frac{1}{4} x^{2}

2 x^{2} - 14 x + 10 = 26

5 r^{2} + 215 r + 3 = 0

What are the solutions to the equation x^2-20x+116=0 ?
The solutions to the equation x^2-20x+116=0 are x=10+4i,x=10-4i
Find the zeros of x^2-20x+116=0
The zeros of x^2-20x+116=0 are x=10+4i,x=10-4i