What are the solutions to the equation 0=x^2+12x+20 ?

The solutions to the equation 0=x^2+12x+20 are x=-2,x=-10

Find the zeros of 0=x^2+12x+20

The zeros of 0=x^2+12x+20 are x=-2,x=-10

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0 = x^{2} + 12 x + 20

x = - 2, x = - 10

Solution steps

0 = x^{2} + 12 x + 20

Switch sides

x^{2} + 12 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 20 = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 \cdot 1}, x_{2} = \frac{- 12 - 8}{2 \cdot 1}

x = \frac{- 12 + 8}{2 \cdot 1} : - 2

x = \frac{- 12 - 8}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 2, x = - 10

\frac{1}{2} x + 2 = \frac{1}{4} x^{2}

2 x^{2} - 14 x + 10 = 26

5 r^{2} + 215 r + 3 = 0

x^{2} + 4 x = 252

2 x^{2} - 22 x - 24 = 0

What are the solutions to the equation 0=x^2+12x+20 ?
The solutions to the equation 0=x^2+12x+20 are x=-2,x=-10
Find the zeros of 0=x^2+12x+20
The zeros of 0=x^2+12x+20 are x=-2,x=-10