What are the solutions to the equation 5x^2+x-16=-10 ?

The solutions to the equation 5x^2+x-16=-10 are x=1,x=-6/5

Find the zeros of 5x^2+x-16=-10

The zeros of 5x^2+x-16=-10 are x=1,x=-6/5

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5 x^{2} + x - 16 = - 10

x = 1, x = - \frac{6}{5}

Decimal Notation

x = 1, x = - 1.2

Solution steps

5 x^{2} + x - 16 = - 10

Move

10

to the left side

5 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 6) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 5}, x_{2} = \frac{- 1 - 11}{2 \cdot 5}

x = \frac{- 1 + 11}{2 \cdot 5} : 1

x = \frac{- 1 - 11}{2 \cdot 5} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{6}{5}

- 0.25 x^{2} + 4 x - 12 = 0

k^{2} + k - 42 = 0

2400 (d) = - d^{2} + 70 d + 1800

x^{2} - 12 x - 17 = 0

- 49 x + x^{2} = 0

What are the solutions to the equation 5x^2+x-16=-10 ?
The solutions to the equation 5x^2+x-16=-10 are x=1,x=-6/5
Find the zeros of 5x^2+x-16=-10
The zeros of 5x^2+x-16=-10 are x=1,x=-6/5