What are the solutions to the equation k^2+k-42=0 ?

The solutions to the equation k^2+k-42=0 are k=6,k=-7

Find the zeros of k^2+k-42=0

The zeros of k^2+k-42=0 are k=6,k=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

k^{2} + k - 42 = 0

k = 6, k = - 7

Solution steps

k^{2} + k - 42 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 42) = 13

k_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 1 + 13}{2 \cdot 1}, k_{2} = \frac{- 1 - 13}{2 \cdot 1}

k = \frac{- 1 + 13}{2 \cdot 1} : 6

k = \frac{- 1 - 13}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

k = 6, k = - 7

2400 (d) = - d^{2} + 70 d + 1800

x^{2} - 12 x - 17 = 0

- 49 x + x^{2} = 0

k^{2} + 10 k - 3 = 0

x, 2 x^{2} - 5 x + 3 = 0

What are the solutions to the equation k^2+k-42=0 ?
The solutions to the equation k^2+k-42=0 are k=6,k=-7
Find the zeros of k^2+k-42=0
The zeros of k^2+k-42=0 are k=6,k=-7