What are the solutions to the equation 6b^2-24b+16=-3b^2 ?

The solutions to the equation 6b^2-24b+16=-3b^2 are b= 4/3

Find the zeros of 6b^2-24b+16=-3b^2

The zeros of 6b^2-24b+16=-3b^2 are b= 4/3

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6 b^{2} - 24 b + 16 = - 3 b^{2}

b = \frac{4}{3}

Decimal Notation

b = 1.33333 \dots

Solution steps

6 b^{2} - 24 b + 16 = - 3 b^{2}

Move

3 b^{2}

to the left side

9 b^{2} - 24 b + 16 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

(- 24)^{2} - 4 \cdot 9 \cdot 16 = 0

b_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 9}

b = \frac{- ( - 24 )}{2 \cdot 9}

\frac{- ( - 24 )}{2 \cdot 9} = \frac{4}{3}

b = \frac{4}{3}

The solution to the quadratic equation is:

b = \frac{4}{3}

c^{2} = 4^{2} + 1 5^{2}

5 m^{2} - 37 m - 72 = 0

48 + 32 t - 16 t^{2} = 0

0 = \frac{1}{2} x^{2}

k^{2} + 10 k + 10 = 9

What are the solutions to the equation 6b^2-24b+16=-3b^2 ?
The solutions to the equation 6b^2-24b+16=-3b^2 are b= 4/3
Find the zeros of 6b^2-24b+16=-3b^2
The zeros of 6b^2-24b+16=-3b^2 are b= 4/3