What are the solutions to the equation k^2+10k+10=9 ?

The solutions to the equation k^2+10k+10=9 are k=-5+2sqrt(6),k=-5-2sqrt(6)

Find the zeros of k^2+10k+10=9

The zeros of k^2+10k+10=9 are k=-5+2sqrt(6),k=-5-2sqrt(6)

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k^{2} + 10 k + 10 = 9

k = - 5 + 26, k = - 5 - 26

Decimal Notation

k = - 0.10102 \dots, k = - 9.89897 \dots

Solution steps

k^{2} + 10 k + 10 = 9

Move

9

to the left side

k^{2} + 10 k + 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 1 = 46

k_{1, 2} = \frac{- 10 \pm 4 6}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 10 + 4 6}{2 \cdot 1}, k_{2} = \frac{- 10 - 4 6}{2 \cdot 1}

k = \frac{- 10 + 4 6}{2 \cdot 1} : - 5 + 26

k = \frac{- 10 - 4 6}{2 \cdot 1} : - 5 - 26

The solutions to the quadratic equation are:

k = - 5 + 26, k = - 5 - 26

c^{2} + 5 c - 24 = 0

18 x^{2} + 24 x = - 8

12 x^{2} - 27 = 0

(3 x - 4)^{2} = 5 x - 6

m^{2} = - 9 m

What are the solutions to the equation k^2+10k+10=9 ?
The solutions to the equation k^2+10k+10=9 are k=-5+2sqrt(6),k=-5-2sqrt(6)
Find the zeros of k^2+10k+10=9
The zeros of k^2+10k+10=9 are k=-5+2sqrt(6),k=-5-2sqrt(6)