What are the solutions to the equation 18x^2+24x=-8 ?

The solutions to the equation 18x^2+24x=-8 are x=-2/3

Find the zeros of 18x^2+24x=-8

The zeros of 18x^2+24x=-8 are x=-2/3

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18 x^{2} + 24 x = - 8

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

18 x^{2} + 24 x = - 8

Move

8

to the left side

18 x^{2} + 24 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 18 \cdot 8}{2 \cdot 18}

2 4^{2} - 4 \cdot 18 \cdot 8 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 18}

x = \frac{- 24}{2 \cdot 18}

\frac{- 24}{2 \cdot 18} = - \frac{2}{3}

x = - \frac{2}{3}

The solution to the quadratic equation is:

x = - \frac{2}{3}

12 x^{2} - 27 = 0

(3 x - 4)^{2} = 5 x - 6

m^{2} = - 9 m

(9.8) (6) = \frac{1}{2} v^{2}

30 (25 - t^{2}) = 450

What are the solutions to the equation 18x^2+24x=-8 ?
The solutions to the equation 18x^2+24x=-8 are x=-2/3
Find the zeros of 18x^2+24x=-8
The zeros of 18x^2+24x=-8 are x=-2/3