What are the solutions to the equation 9x^2+5x+9/4 =0 ?

The solutions to the equation 9x^2+5x+9/4 =0 are x=-5/18+i(sqrt(14))/9 ,x=-5/18-i(sqrt(14))/9

Find the zeros of 9x^2+5x+9/4 =0

The zeros of 9x^2+5x+9/4 =0 are x=-5/18+i(sqrt(14))/9 ,x=-5/18-i(sqrt(14))/9

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9 x^{2} + 5 x + \frac{9}{4} = 0

x = - \frac{5}{18} + i \frac{14}{9}, x = - \frac{5}{18} - i \frac{14}{9}

Solution steps

9 x^{2} + 5 x + \frac{9}{4} = 0

Multiply both sides by

4

36 x^{2} + 20 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 36 \cdot 9}{2 \cdot 36}

Simplify

2 0^{2} - 4 \cdot 36 \cdot 9 : 814 i

x_{1, 2} = \frac{- 20 \pm 8 14 i}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- 20 + 8 14 i}{2 \cdot 36}, x_{2} = \frac{- 20 - 8 14 i}{2 \cdot 36}

x = \frac{- 20 + 8 14 i}{2 \cdot 36} : - \frac{5}{18} + i \frac{14}{9}

x = \frac{- 20 - 8 14 i}{2 \cdot 36} : - \frac{5}{18} - i \frac{14}{9}

The solutions to the quadratic equation are:

x = - \frac{5}{18} + i \frac{14}{9}, x = - \frac{5}{18} - i \frac{14}{9}

x^{2} - 15 x + 4 = 0

m^{2} + 8 = 0

y^{2} - y - 42 = 0

(x - 2)^{2} + 3 (x + 4) (x - 4) = 2 (x + 3) (x - 1)

9^{2} = 7^{2} + b^{2}

What are the solutions to the equation 9x^2+5x+9/4 =0 ?
The solutions to the equation 9x^2+5x+9/4 =0 are x=-5/18+i(sqrt(14))/9 ,x=-5/18-i(sqrt(14))/9
Find the zeros of 9x^2+5x+9/4 =0
The zeros of 9x^2+5x+9/4 =0 are x=-5/18+i(sqrt(14))/9 ,x=-5/18-i(sqrt(14))/9